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Pendulum Calculator

Calculate the period, frequency, length, or gravity for simple and compound physical pendulums.

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The Physics of Pendulum Oscillations

A pendulum is a simple mechanical system consisting of a mass suspended from a pivot point so that it can swing freely. When displaced from its resting position, gravity acts as a restoring force, pulling it back towards the equilibrium point, causing it to oscillate back and forth. Pendulums have historical significance in timekeeping (clocks), seismology, and the measurement of local gravity.

Simple Pendulum Calculations

A simple pendulum is idealized as a point mass (bob) suspended from a massless, rigid cord of length $L$. Assuming small swing angles (typically below 15 degrees), the system can be modeled using simple harmonic motion equations:

1. Pendulum Period (T)

The period is the time required for the bob to complete one full back-and-forth oscillation:

$$T = 2\pi \sqrt{\frac{L}{g}}$$

Where $L$ is the length of the cord and $g$ is the local acceleration due to gravity. Note that the mass of the bob does not affect the period.

2. Oscillation Frequency (f)

The frequency is the number of complete cycles per second, measured in Hertz (Hz):

$$f = \frac{1}{T} = \frac{1}{2\pi} \sqrt{\frac{g}{L}}$$

3. Finding Pendulum Length (L)

To design a pendulum with a specific target period, the required cord length is computed by rearranging the period formula:

$$L = g \cdot \left(\frac{T}{2\pi}\right)^2$$

Physical (Compound) Pendulum Calculations

Real-world pendulums are not point masses suspended by massless strings. A physical pendulum consists of a rigid body of total mass $m$ pivoting about a fixed point. Its period is determined by its moment of inertia $I$ and the distance $d$ from the pivot to the center of mass:

$$T = 2\pi \sqrt{\frac{I}{m \cdot g \cdot d}}$$

Where:

  • $I$ is the moment of inertia about the pivot axis ($kg \cdot m^2$)
  • $m$ is the total mass of the object ($kg$)
  • $d$ is the distance from the pivot to the center of mass ($m$)
  • $g$ is the local gravity ($m/s^2$)

Frequently Asked Questions

Why doesn't the mass of the bob affect a simple pendulum's period?

In a simple pendulum, both the restoring force (gravity) and the resistance to acceleration (inertia) are directly proportional to the mass. As a result, the mass terms cancel out in the equation of motion, meaning a heavy bob and a light bob will swing with the exact same period if their lengths are identical.

What is the small-angle approximation in pendulum physics?

The simple pendulum formula uses the approximation $\sin(\theta) \approx \theta$, which is highly accurate for displacement angles below 15 degrees. For larger swing angles, the restoring force becomes non-linear, and the actual period increases slightly compared to the calculated value.

What is a seconds pendulum?

A seconds pendulum is a pendulum whose period is exactly two seconds — one second for the swing forward and one second for the return swing. On Earth's surface, a seconds pendulum has a length of approximately 0.994 meters (39.1 inches).

How does gravity affect the pendulum period?

Because gravity is in the denominator of the period equation, stronger gravity decreases the period (making the pendulum swing faster), while weaker gravity increases the period. For instance, the same pendulum will swing much slower on the Moon ($g \approx 1.62 \, m/s^2$) than on Earth.