Bridge Rectifier Calculator
Calculate peak, average, and RMS output voltage of a bridge rectifier from AC input with and without load capacitor.
What Is a Bridge Rectifier?
A full-wave bridge rectifier uses four diodes to convert AC to pulsating DC. Both halves of the AC cycle contribute to the output, doubling the effective frequency compared with a half-wave rectifier.
Bridge Rectifier Voltage Formulas
Peak voltage from RMS input:
$$V_{\text{peak}} = V_{\text{rms}} \times \sqrt{2}$$Average DC output (ideal, no diode drop):
$$V_{\text{avg}} = \frac{2}{\pi} \times V_{\text{peak}}$$With silicon diode forward drops:
$$V_{\text{avg}} \approx V_{\text{peak}} - 2V_d$$RMS output of the unfiltered full-wave waveform:
$$V_{\text{rms,out}} = \frac{V_{\text{peak}}}{\sqrt{2}}$$Example: 120 V RMS input gives \(V_{\text{peak}} \approx 169.71\) V and ideal \(V_{\text{avg}} \approx 107.99\) V.
Related tools: Voltage Converter and Power Converter.
Frequently Asked Questions
Why multiply RMS by √2?
For a sine wave, peak voltage equals RMS times √2. The bridge rectifier output peak tracks the input peak (minus small diode drops).
What is V_d?
It is the forward voltage drop of one diode, typically about 0.7 V for silicon. Two diodes conduct per half cycle in a bridge, so subtract 2V_d from peak for a quick average estimate.
Does a capacitor change the average voltage?
Yes. A smoothing capacitor holds the output near peak between pulses, raising average DC toward V_peak minus ripple. This calculator shows the unfiltered full-wave values.
Why is V_rms,out equal to V_rms,in?
Full-wave rectification folds the negative half into the positive half. The RMS of that waveform equals V_peak/√2, which matches the original sine RMS.
Where are bridge rectifiers used?
They are common in linear and switching power supplies, battery chargers, and anywhere AC mains must become DC.