Polar Moment of Inertia Calculator
Calculate polar moment of inertia for solid and hollow circular shafts used in torsion analysis with step-by-step formulas.
Polar Moment of Inertia for Circular Shafts
The polar moment of inertia, denoted J, describes how a circular cross-section resists torsion. It appears in shear stress and twist equations for drive shafts, drill rods, and other torque-loaded members.
Formulas
Solid circular shaft:
$$J = \frac{\pi D^4}{32}$$Hollow circular shaft:
$$J = \frac{\pi}{32}(D^4 - d^4)$$\(D\) is the outer diameter and \(d\) is the inner diameter. The result has units of length to the fourth power, such as mm⁴ or in⁴.
Engineering Use
Shear stress in a circular shaft is \(\tau = T\rho / J\), where \(T\) is applied torque and \(\rho\) is radial distance from the axis. Angle of twist is \(\phi = TL / (JG)\), where \(L\) is shaft length and \(G\) is shear modulus. These relations apply to circular sections where the cross-section remains plane under torque.
Frequently Asked Questions
What is the polar moment of inertia of a 5 cm diameter solid shaft?
Using J = πD⁴/32, a 5 cm diameter solid shaft has J ≈ 61.36 cm⁴.
How is polar moment different from area moment of inertia?
Polar moment governs torsion resistance. Area moment of inertia governs bending deflection. For a circle, J equals the sum of the two principal area moments.
Can I use these formulas for rectangular bars?
No. The torsion equations that use J are derived for circular cross-sections. Noncircular shapes need a torsion constant instead.
What units should I use?
Use consistent length units throughout. Common choices are mm⁴ in metric drawings and in⁴ in US customary practice.
Does a hollow shaft always have lower J than a solid shaft?
For the same outer diameter, yes, because material is removed from the center. Hollow shafts can still be efficient when weight savings matter.