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Polar Moment of Inertia Calculator

Calculate polar moment of inertia for solid and hollow circular shafts used in torsion analysis with step-by-step formulas.

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Polar Moment of Inertia for Circular Shafts

The polar moment of inertia, denoted J, describes how a circular cross-section resists torsion. It appears in shear stress and twist equations for drive shafts, drill rods, and other torque-loaded members.

Formulas

Solid circular shaft:

$$J = \frac{\pi D^4}{32}$$

Hollow circular shaft:

$$J = \frac{\pi}{32}(D^4 - d^4)$$

\(D\) is the outer diameter and \(d\) is the inner diameter. The result has units of length to the fourth power, such as mm⁴ or in⁴.

Engineering Use

Shear stress in a circular shaft is \(\tau = T\rho / J\), where \(T\) is applied torque and \(\rho\) is radial distance from the axis. Angle of twist is \(\phi = TL / (JG)\), where \(L\) is shaft length and \(G\) is shear modulus. These relations apply to circular sections where the cross-section remains plane under torque.

Frequently Asked Questions

What is the polar moment of inertia of a 5 cm diameter solid shaft?

Using J = πD⁴/32, a 5 cm diameter solid shaft has J ≈ 61.36 cm⁴.

How is polar moment different from area moment of inertia?

Polar moment governs torsion resistance. Area moment of inertia governs bending deflection. For a circle, J equals the sum of the two principal area moments.

Can I use these formulas for rectangular bars?

No. The torsion equations that use J are derived for circular cross-sections. Noncircular shapes need a torsion constant instead.

What units should I use?

Use consistent length units throughout. Common choices are mm⁴ in metric drawings and in⁴ in US customary practice.

Does a hollow shaft always have lower J than a solid shaft?

For the same outer diameter, yes, because material is removed from the center. Hollow shafts can still be efficient when weight savings matter.