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Electric Field of a Point Charge Calculator

Calculate electric field strength at a distance from a point charge using Coulomb's law E = kQ/r².

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Electric Field of a Point Charge

A point charge creates a radial electric field that decreases with the square of distance. This is a direct consequence of Coulomb's law and Gauss's law for electrostatics.

Field Formula

$$E = \frac{kQ}{r^2}$$

\(k \approx 8.99 \times 10^9\) N·m²/C² is Coulomb's constant, \(Q\) is charge in coulombs, and \(r\) is distance in meters. The field points away from positive charges and toward negative charges. Units are N/C, equivalent to V/m.

Example: a 1 µC charge at 10 cm distance produces \(E = (8.99 \times 10^9)(10^{-6}) / (0.1)^2 \approx 8.99 \times 10^5\) N/C.

Force on a Test Charge

The force on a test charge \(q\) in this field is \(F = qE\). A 1 C test charge at that location would experience about \(8.99 \times 10^5\) N of force.

Frequently Asked Questions

What is Coulomb's constant?

Coulomb's constant k ≈ 8.99 × 10⁹ N·m²/C² relates electrostatic force and field strength in vacuum. It equals 1/(4πε₀) where ε₀ is the permittivity of free space.

Why does the field fall off as 1/r²?

Field lines spread over a sphere whose area grows as 4πr². The same total flux is distributed over a larger area, so field strength decreases with the square of distance.

Are N/C and V/m the same?

Yes. One newton per coulomb equals one volt per meter. Both measure electric field strength.

What happens with a negative charge?

The field magnitude is the same, but the direction reverses. Negative charges attract field lines inward rather than radiating outward.

Does this formula work inside a conductor?

For a point charge in vacuum or uniform dielectric, yes. Inside conductors at electrostatic equilibrium, the internal field is zero regardless of external charges.