Electric Field of a Point Charge Calculator
Calculate electric field strength at a distance from a point charge using Coulomb's law E = kQ/r².
Electric Field of a Point Charge
A point charge creates a radial electric field that decreases with the square of distance. This is a direct consequence of Coulomb's law and Gauss's law for electrostatics.
Field Formula
$$E = \frac{kQ}{r^2}$$\(k \approx 8.99 \times 10^9\) N·m²/C² is Coulomb's constant, \(Q\) is charge in coulombs, and \(r\) is distance in meters. The field points away from positive charges and toward negative charges. Units are N/C, equivalent to V/m.
Example: a 1 µC charge at 10 cm distance produces \(E = (8.99 \times 10^9)(10^{-6}) / (0.1)^2 \approx 8.99 \times 10^5\) N/C.
Force on a Test Charge
The force on a test charge \(q\) in this field is \(F = qE\). A 1 C test charge at that location would experience about \(8.99 \times 10^5\) N of force.
Frequently Asked Questions
What is Coulomb's constant?
Coulomb's constant k ≈ 8.99 × 10⁹ N·m²/C² relates electrostatic force and field strength in vacuum. It equals 1/(4πε₀) where ε₀ is the permittivity of free space.
Why does the field fall off as 1/r²?
Field lines spread over a sphere whose area grows as 4πr². The same total flux is distributed over a larger area, so field strength decreases with the square of distance.
Are N/C and V/m the same?
Yes. One newton per coulomb equals one volt per meter. Both measure electric field strength.
What happens with a negative charge?
The field magnitude is the same, but the direction reverses. Negative charges attract field lines inward rather than radiating outward.
Does this formula work inside a conductor?
For a point charge in vacuum or uniform dielectric, yes. Inside conductors at electrostatic equilibrium, the internal field is zero regardless of external charges.