Circumcenter of a Triangle Calculator
Calculate the circumcenter coordinates, circumradius, circumcircle equation, and perpendicular bisector equations of any triangle from three vertices or side lengths.
What Is the Circumcenter of a Triangle?
The circumcenter of a triangle is the point where the three perpendicular bisectors of the triangle's sides intersect. It is designated by the letter $U$ (or $O$) and serves as the exact center of the circumscribed circle (or circumcircle), which is the unique circle that passes through all three vertices of the triangle.
Because the circumcenter is equidistant from all three vertices $A$, $B$, and $C$, the distance from the circumcenter to any vertex is equal to the triangle's circumradius ($R$):
$$R = |UA| = |UB| = |UC|$$
Circumcenter Formulas and Coordinate Geometry
Given three vertices in the Cartesian plane $A(x_1, y_1)$, $B(x_2, y_2)$, and $C(x_3, y_3)$, you can calculate the exact circumcenter coordinates $(U_x, U_y)$ using the system of perpendicular bisectors or Cramer's determinant method:
First, compute the denominator determinant $D$:
$$D = 2 \cdot [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]$$
If $D = 0$, the three points are collinear and cannot form a triangle. Otherwise, the coordinates $U_x$ and $U_y$ are:
$$U_x = \frac{(x_1^2 + y_1^2)(y_2 - y_3) + (x_2^2 + y_2^2)(y_3 - y_1) + (x_3^2 + y_3^2)(y_1 - y_2)}{D}$$
$$U_y = \frac{(x_1^2 + y_1^2)(x_3 - x_2) + (x_2^2 + y_2^2)(x_1 - x_3) + (x_3^2 + y_3^2)(x_2 - x_1)}{D}$$
Circumradius Formula from Side Lengths and Area
When you know the three side lengths $a$, $b$, and $c$, the circumradius $R$ can be found directly without coordinates using the triangle's area:
$$R = \frac{a \cdot b \cdot c}{4 \cdot \text{Area}}$$
Where the area is calculated using Heron's formula:
$$s = \frac{a + b + c}{2}$$
$$\text{Area} = \sqrt{s(s - a)(s - b)(s - c)}$$
Position of the Circumcenter Relative to Triangle Type
The location of the circumcenter depends entirely on the angle classification of the triangle:
- Acute Triangle: All three angles are less than 90 degrees. The circumcenter lies strictly inside the triangle.
- Right Triangle: One angle is exactly 90 degrees. The circumcenter lies directly on the midpoint of the hypotenuse, and the circumradius is exactly half the hypotenuse length ($R = c / 2$).
- Obtuse Triangle: One angle is greater than 90 degrees. The circumcenter lies outside the triangle opposite the obtuse angle.
Circumcircle Equation
Once you have the circumcenter coordinates $(U_x, U_y)$ and the circumradius $R$, you can express the equation of the circumscribed circle in Standard Form:
$$(x - U_x)^2 + (y - U_y)^2 = R^2$$
Expanding this equation yields the General Form:
$$x^2 + y^2 - 2U_x x - 2U_y y + (U_x^2 + U_y^2 - R^2) = 0$$
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Frequently Asked Questions
What is the difference between the circumcenter and the incenter?
The circumcenter is the center of the circumcircle (which surrounds the triangle and passes through all three vertices), formed by the intersection of perpendicular bisectors. The incenter is the center of the incircle (which is inscribed inside the triangle tangent to all three sides), formed by the intersection of the angle bisectors.
Can the circumcenter lie outside the triangle?
Yes. For any obtuse triangle (where one internal angle exceeds 90 degrees), the perpendicular bisectors meet outside the perimeter of the triangle.
Where is the circumcenter in a right-angled triangle?
In any right-angled triangle, Thales's theorem dictates that the circumcenter is located exactly at the midpoint of the hypotenuse, and the circumradius is equal to half the length of the hypotenuse.
What happens if three points are collinear?
If three points lie along the same straight line, the determinant D equals zero. A circumscribed circle cannot be constructed because no unique circle passes through three distinct collinear points.
How do perpendicular bisectors relate to the circumcenter?
A perpendicular bisector of a line segment is the locus of all points equidistant from the two endpoints. Because the circumcenter must be equidistant from all three triangle vertices simultaneously, it must be the point where all three perpendicular bisectors meet.